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(D) When $2$ dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.Let $A$ be the event of getting an odd number as the su

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$\frac{1}{2}$

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(D) When $2$ dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.Let $A$ be the event of getting an odd number as the sum.The sum of two dice is odd if one die shows an even number and the other shows an odd number.The possible outcomes for an odd sum are:$(1,2), (1,4), (1,6), (2,1), (2,3), (2,5), (3,2), (3,4), (3,6), (4,1), (4,3), (4,5), (5,2), (5,4), (5,6), (6,1), (6,3), (6,5)$.Counting these,we get $n(A) = 18$.The probability of the event $A$ is given by $P(A) = \frac{n(A)}{n(S)}$.$P(A) = \frac{18}{36} = \frac{1}{2}$.

$2$ dice are thrown. Find the probability of getting an odd number as the sum.

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