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(A) When $2$ dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.Let $A$ be the event of getting $6$ as the product of t

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$\frac{1}{9}$

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(A) When $2$ dice are thrown,the total number of possible outcomes is $n(S) = 6 	imes 6 = 36$.Let $A$ be the event of getting $6$ as the product of the numbers on the two dice.The pairs $(x, y)$ such that $x 	imes y = 6$ are $(1, 6), (6, 1), (2, 3),$ and $(3, 2)$.Thus,the number of favorable outcomes is $n(A) = 4$.The probability of the event $A$ is given by $P(A) = \frac{n(A)}{n(S)}$.$P(A) = \frac{4}{36} = \frac{1}{9}$.

$2$ dice are thrown. Find the probability of getting $6$ as the product.

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