I. 3x^2 - 20x - 32 = 0II. 2y^2 - 3y - 20 = 0 | vedclass

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(D) For equation $I: 3x^2 - 20x - 32 = 0$$3x^2 - 24x + 4x - 32 = 0$$3x(x - 8) + 4(x - 8) = 0$$(3x + 4)(x - 8) = 0$So,$x = -4/3$ or $x = 8$.For equatio

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Relationship between $x$ and $y$ cannot be established

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(D) For equation $I: 3x^2 - 20x - 32 = 0$$3x^2 - 24x + 4x - 32 = 0$$3x(x - 8) + 4(x - 8) = 0$$(3x + 4)(x - 8) = 0$So,$x = -4/3$ or $x = 8$.For equation $II: 2y^2 - 3y - 20 = 0$$2y^2 - 8y + 5y - 20 = 0$$2y(y - 4) + 5(y - 4) = 0$$(2y + 5)(y - 4) = 0$So,$y = -5/2$ or $y = 4$.Comparing the values:If $x = 8$,then $x > y$ (since $y$ is $4$ or $-2.5$).If $x = -1.33$,then $x > y$ (since $y = 4$) but $x Since the relationship changes depending on the roots chosen,the relationship between $x$ and $y$ cannot be established.

$I. 3x^2 - 20x - 32 = 0$
$II. 2y^2 - 3y - 20 = 0$

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$I. 3x^2 - 20x - 32 = 0$$II. 2y^2 - 3y - 20 = 0$