Q is 14, km south and 16, km west of P. Find | vedclass

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(C) The points $P$,$R$,and $Q$ form a right-angled triangle $	riangle PRQ$,where $\angle PRQ = 90^\circ$.Given $PR = 14\, km$ and $QR = 16\, km$.Usin

Vedclass · Accepted Answer

$21.2$

Vedclass · Answer

(C) The points $P$,$R$,and $Q$ form a right-angled triangle $	riangle PRQ$,where $\angle PRQ = 90^\circ$.Given $PR = 14\, km$ and $QR = 16\, km$.Using the Pythagorean theorem,the distance $PQ$ is given by:$PQ = \sqrt{PR^2 + QR^2}$$PQ = \sqrt{14^2 + 16^2}$$PQ = \sqrt{196 + 256}$$PQ = \sqrt{452}$$PQ \approx 21.26\, km$.Rounding to one decimal place,we get $21.2\, km$.

$Q$ is $14\, km$ south and $16\, km$ west of $P$. Find the distance of $Q$ from $P$ (in $km$).

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