0.01 M solutions of glucose,phenol,and potas | vedclass

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Question

(D) The boiling point elevation is a colligative property,which depends on the van't Hoff factor $(i)$.$KCl$ is a strong electrolyte that dissociates

Vedclass · Accepted Answer

Potassium chloride solution $>$ Phenol solution $>$ Glucose solution

Vedclass · Answer

(D) The boiling point elevation is a colligative property,which depends on the van't Hoff factor $(i)$.$KCl$ is a strong electrolyte that dissociates completely into $K^+$ and $Cl^-$ ions $(i \approx 2)$.Phenol $(C_6H_5OH)$ is a weak acid that undergoes partial dissociation in water,providing more particles than a non-electrolyte $(i > 1)$.Glucose $(C_6H_{12}O_6)$ is a non-electrolyte and does not dissociate $(i = 1)$.Since the boiling point elevation $\Delta T_b = i 	imes K_b 	imes m$,the order of boiling points is $KCl > C_6H_5OH > C_6H_{12}O_6$.

$0.01 \ M$ solutions of glucose,phenol,and potassium chloride were prepared in water. The boiling points of these solutions follow the order:

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