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(D) The father has blood group $A$, which can have the genotype $I^A I^A$ or $I^A i$. The mother has blood group $AB$, which has the genotype $I^A I^B

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$I^B i$

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(D) The father has blood group $A$, which can have the genotype $I^A I^A$ or $I^A i$. The mother has blood group $AB$, which has the genotype $I^A I^B$. The child has blood group $B$, which must have the genotype $I^B I^B$ or $I^B i$. Since the child has blood group $B$, they must have inherited the $I^B$ allele from the mother. To have blood group $B$, the child must have inherited an $i$ allele from the father (since the father cannot pass on an $I^B$ allele). Therefore, the father's genotype must be $I^A i$. The cross is $I^A i 	imes I^A I^B$. The possible genotypes for the offspring are $I^A I^A$, $I^A I^B$, $I^A i$, and $I^B i$. The child with blood group $B$ must have the genotype $I^B i$.

If a man with blood group $A$ marries a woman with blood group $AB$, and their first child has blood group $B$, what is the genotype of the child?

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