Genes p, q, and r are arranged on a chromosom | vedclass

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(D) The recombination frequency between two genes is directly proportional to the distance between them on the chromosome.Given:Recombination frequenc

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$q-p-r$

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(D) The recombination frequency between two genes is directly proportional to the distance between them on the chromosome.Given:Recombination frequency between $p$ and $q = 10 \% \implies$ distance $= 10 	ext{ map units}$.Recombination frequency between $q$ and $r = 20 \% \implies$ distance $= 20 	ext{ map units}$.Recombination frequency between $p$ and $r = 10 \% \implies$ distance $= 10 	ext{ map units}$.Since the distance between $q$ and $r$ $(20 	ext{ units})$ is the sum of the distances between $p$ and $q$ $(10 	ext{ units})$ and $p$ and $r$ $(10 	ext{ units})$,it implies that gene $p$ lies between $q$ and $r$.Therefore,the order of the genes on the chromosome is $q-p-r$ or $r-p-q$.

Genes $p, q,$ and $r$ are arranged on a chromosome. If the recombination frequency between $p$ and $q$ is $10 \%$,the recombination frequency between $q$ and $r$ is $20 \%$,and the recombination frequency between $p$ and $r$ is $10 \%$,what is the order of the genes on the chromosome?

Similar Questions

Who mapped the position of genes on chromosomes by using the frequency of recombination between gene pairs on the same chromosome as a measure of the distance between genes?

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