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(B) In a dihybrid cross between two heterozygous parents $(RrYy 	imes RrYy)$,the phenotypic ratio is $9:3:3:1$. However,the genotypic distribution in

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$2$

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(B) In a dihybrid cross between two heterozygous parents $(RrYy 	imes RrYy)$,the phenotypic ratio is $9:3:3:1$. However,the genotypic distribution in the $F_2$ generation follows the Punnett square grid of $16$ squares. The genotype $rrYy$ represents a plant that is homozygous recessive for the first trait $(rr)$ and heterozygous for the second trait $(Yy)$. In the $F_2$ Punnett square,the frequency of the $rrYy$ genotype is $2$ out of $16$ (specifically,the combinations $rY$ and $ry$ from one parent crossing with $rY$ and $ry$ from the other result in $rrYY, rrYy, rrYy, rryy$). Thus,there are $2$ offspring with the genotype $rrYy$.

In Mendel's dihybrid cross experiment,out of $16$ offspring,how many offspring possess the genotype $rrYy$?

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