If the population size at time N_{t+1} is 100 | vedclass

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(C) The formula for population growth is $N_{t+1} = N_t + (B - D)$,where $B$ is the number of births and $D$ is the number of deaths.Given,$N_{t+1} =

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$400$

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(C) The formula for population growth is $N_{t+1} = N_t + (B - D)$,where $B$ is the number of births and $D$ is the number of deaths.Given,$N_{t+1} = 1000$ and $N_t = 800$.Substituting these values,we get $1000 = 800 + (B - D)$,which simplifies to $B - D = 200$.According to the problem,the death rate $(D)$ is $50\%$ less than the birth rate $(B)$,which means $D = B - 0.5B = 0.5B$.Substituting $D = 0.5B$ into the equation $B - D = 200$,we get $B - 0.5B = 200$.$0.5B = 200$,therefore $B = 400$.Thus,the number of births is $400$.

If the population size at time $N_{t+1}$ is $1000$,and there is no immigration or emigration,and the death rate is $50\%$ less than the birth rate,and the population size $1$ year ago $(N_t)$ was $800$,what is the number of births?

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