_{13}^{27}Al is a stable isotope. _{13}^{29}A | vedclass

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(B) The atomic number $(Z)$ of $_{13}^{29}Al$ is $13$ and the number of neutrons $(n)$ is $29 - 13 = 16$.The $\frac{n}{p}$ ratio is $\frac{16}{13} \ap

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$\beta$-emission

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(B) The atomic number $(Z)$ of $_{13}^{29}Al$ is $13$ and the number of neutrons $(n)$ is $29 - 13 = 16$.The $\frac{n}{p}$ ratio is $\frac{16}{13} \approx 1.23$.For light elements,the stable $\frac{n}{p}$ ratio is approximately $1$.Since the $\frac{n}{p}$ ratio of $_{13}^{29}Al$ is higher than the stable ratio,it lies above the belt of stability.To achieve stability,it converts a neutron into a proton by emitting a $\beta$-particle $(_{-1}^{0}e)$: $_{13}^{29}Al \rightarrow _{14}^{29}Si + _{-1}^{0}e$.

$_{13}^{27}Al$ is a stable isotope. $_{13}^{29}Al$ is expected to disintegrate by

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