$5 \cos A = 4 \sin A$,then $\tan A = \ldots$
- A$\frac{1}{20}$
- B$\frac{1}{4}$
- C$\frac{4}{5}$
- D$\frac{5}{4}$
Explore More
Similar Questions
Which of the following pairs is correct for trigonometric inter-relationships?
$1. \cos \theta$ $a. \frac{\cos \theta}{\sin \theta}$ $2. \tan \theta$ $b. \frac{1}{\csc \theta}$ $3. \cot \theta$ $c. \frac{1}{\sec \theta}$ $4. \sin \theta$ $d. \frac{1}{\cot \theta}$ $e. \sin \theta \cdot \cos \theta$
| $1. \cos \theta$ | $a. \frac{\cos \theta}{\sin \theta}$ |
| $2. \tan \theta$ | $b. \frac{1}{\csc \theta}$ |
| $3. \cot \theta$ | $c. \frac{1}{\sec \theta}$ |
| $4. \sin \theta$ | $d. \frac{1}{\cot \theta}$ |
| $e. \sin \theta \cdot \cos \theta$ |
Easy
View Solution$\frac{1}{\tan ^{2} \theta}+1 = \dots$
Easy
View SolutionIf $\sin \theta + \cos \theta = \sqrt{3}$,then prove that $\tan \theta + \cot \theta = 1$.
Medium
View Solution$\sin 60^{\circ} \cdot \cos 30^{\circ} + \cos 60^{\circ} \cdot \sin 30^{\circ} = ..........$
Easy
View SolutionIf $3 \sin \theta = 4 \cos \theta$,then $\tan \theta = \ldots$
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo