tan (90^circ - theta) = ldots ldots ldots | vedclass

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(B) In trigonometry,the trigonometric ratios of complementary angles are defined as follows:$\sin (90^\circ - 	heta) = \cos 	heta$$\cos (90^\circ -

Vedclass · Accepted Answer

$\cot 	heta$

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(B) In trigonometry,the trigonometric ratios of complementary angles are defined as follows:$\sin (90^\circ - 	heta) = \cos 	heta$$\cos (90^\circ - 	heta) = \sin 	heta$$	an (90^\circ - 	heta) = \cot 	heta$$\cot (90^\circ - 	heta) = 	an 	heta$$\sec (90^\circ - 	heta) = \operatorname{cosec} 	heta$$\operatorname{cosec} (90^\circ - 	heta) = \sec 	heta$Therefore,$	an (90^\circ - 	heta) = \cot 	heta$.

$\tan (90^\circ - \theta) = \ldots \ldots \ldots$

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