sec 55^{circ} cdot sin 35^{circ} + cos 35^{ci | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) આપણે જાણીએ છીએ કે $\sec 	heta = \frac{1}{\cos 	heta}$ અને $\operatorname{cosec} 	heta = \frac{1}{\sin 	heta}$ થાય છે.વળી,$\sin(90^{\circ} -

Vedclass · Accepted Answer

$2$

Vedclass · Answer

(D) આપણે જાણીએ છીએ કે $\sec 	heta = \frac{1}{\cos 	heta}$ અને $\operatorname{cosec} 	heta = \frac{1}{\sin 	heta}$ થાય છે.વળી,$\sin(90^{\circ} - 	heta) = \cos 	heta$ અને $\cos(90^{\circ} - 	heta) = \sin 	heta$ થાય છે.આપેલ પદાવલિ: $\sec 55^{\circ} \cdot \sin 35^{\circ} + \cos 35^{\circ} \cdot \operatorname{cosec} 55^{\circ}$.$55^{\circ}$ ને $(90^{\circ} - 35^{\circ})$ તરીકે લખતા:$= \sec(90^{\circ} - 35^{\circ}) \cdot \sin 35^{\circ} + \cos 35^{\circ} \cdot \operatorname{cosec}(90^{\circ} - 35^{\circ})$$= \operatorname{cosec} 35^{\circ} \cdot \sin 35^{\circ} + \cos 35^{\circ} \cdot \sec 35^{\circ}$કારણ કે $\operatorname{cosec} 35^{\circ} = \frac{1}{\sin 35^{\circ}}$ અને $\sec 35^{\circ} = \frac{1}{\cos 35^{\circ}}$ હોવાથી:$= \left(\frac{1}{\sin 35^{\circ}}ight) \cdot \sin 35^{\circ} + \cos 35^{\circ} \cdot \left(\frac{1}{\cos 35^{\circ}}ight)$$= 1 + 1 = 2$.

$\sec 55^{\circ} \cdot \sin 35^{\circ} + \cos 35^{\circ} \cdot \operatorname{cosec} 55^{\circ} = \ldots \ldots \ldots \ldots$

Similar Questions

$\sin (90^\circ - \theta) = \ldots \ldots \ldots$

જો $\sin \theta + \cos \theta = \sqrt{3}$ હોય,તો સાબિત કરો કે $\tan \theta + \cot \theta = 1$.

$\operatorname{cosec} 40^{\circ} = \ldots \ldots \ldots \ldots$

જો $3 \sin \theta = 4 \cos \theta$ હોય,તો $\tan \theta = \ldots$

સાબિત કરો કે,$\tan \theta + \tan (90^{\circ} - \theta) = \sec \theta \sec (90^{\circ} - \theta)$

Vedclass Test Series

Exam Paper Generator

Online Exam Module