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(D) To find the zeros of the polynomial $p(x) = x^{3} + 7x^{2} + 11x + 5$,we test the given options by substituting them into the polynomial.If $x = -

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(D) To find the zeros of the polynomial $p(x) = x^{3} + 7x^{2} + 11x + 5$,we test the given options by substituting them into the polynomial.If $x = -1$:$p(-1) = (-1)^{3} + 7(-1)^{2} + 11(-1) + 5$$p(-1) = -1 + 7(1) - 11 + 5$$p(-1) = -1 + 7 - 11 + 5$$p(-1) = 12 - 12 = 0$Since $p(-1) = 0$,$x = -1$ is a zero of the polynomial $p(x)$.

$\ldots \ldots$ is one of the zeros of $p(x) = x^{3} + 7x^{2} + 11x + 5$.

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