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(A) $1$. Let the sum of the ages of the mother,father,and two children $x$ years ago be $y$.$2$. The total number of people is $4$ (mother,father,and

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$y + 4x + 4z$

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(A) $1$. Let the sum of the ages of the mother,father,and two children $x$ years ago be $y$.$2$. The total number of people is $4$ (mother,father,and two children).$3$. Since $x$ years have passed since that time,each person has aged by $x$ years. Therefore,the current sum of their ages is $y + (4 	imes x) = y + 4x$.$4$. We need to find the sum of their ages after $z$ years from the current time.$5$. In $z$ years,each of the $4$ people will age by $z$ years. Thus,the total increase in the sum of their ages will be $4 	imes z = 4z$.$6$. The sum of their ages after $z$ years will be $(y + 4x) + 4z = y + 4x + 4z$.

$x$ years ago,the sum of the ages of a mother,father,and two children was $y$ years. What will be the sum of their ages after $z$ years?

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