Delta ABC sim Delta DEF for the correspondenc | vedclass

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(C) In $\Delta DEF$,the sum of angles is $180^{\circ}$.Given $m \angle E + m \angle F = 130^{\circ}$.Therefore,$m \angle D = 180^{\circ} - (m \angle E

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(C) In $\Delta DEF$,the sum of angles is $180^{\circ}$.Given $m \angle E + m \angle F = 130^{\circ}$.Therefore,$m \angle D = 180^{\circ} - (m \angle E + m \angle F) = 180^{\circ} - 130^{\circ} = 50^{\circ}$.Since the correspondence $ABC \leftrightarrow FDE$ represents a similarity,the corresponding angles are equal.Specifically,$\angle B$ corresponds to $\angle D$.Therefore,$m \angle B = m \angle D = 50^{\circ}$.

$\Delta ABC \sim \Delta DEF$ for the correspondence $ABC \leftrightarrow FDE$. If $m \angle E + m \angle F = 130^{\circ}$,then $m \angle B = \dots$ (in $^{\circ}$)

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