$TSA$ of a cone with radius $4\, cm$ and height $3\, cm$ is $\ldots \ldots \ldots \ldots cm^{2}$. (in $\pi$)

  • A
    $9$
  • B
    $18$
  • C
    $27$
  • D
    $36$

Explore More

Similar Questions

The radii of the ends of a frustum of a cone of height $h \text{ cm}$ are $r_{1} \text{ cm}$ and $r_{2} \text{ cm}$. The volume in $\text{cm}^{3}$ of the frustum of the cone is:

Write 'True' or 'False' and justify your answer:
The actual capacity of a vessel as shown in the figure is equal to the difference between the volume of the cylinder and the volume of the hemisphere.

$A$ cone and a cylinder have equal radii and equal heights. Then,the ratio of their volumes is $\ldots \ldots \ldots . .$

The $CSA$ (Curved Surface Area) of a hemisphere is equal to $\ldots \ldots \ldots$

Total surface area of a cylinder with radius $7 \, cm$ and height $13 \, cm$ is $\ldots \ldots \ldots \ldots \, cm^{2}$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo