$8 NH_{3} + 3 Cl_{2} \rightarrow X$ (Excess $NH_{3}$)
$NH_{3} + 3 Cl_{2} \rightarrow Y$ (Excess $Cl_{2}$)
What are $X$ and $Y$ in the above reactions?

• A
  $X = 6 NH_{4}Cl + N_{2} ; Y = NCl_{3} + 3 HCl$
• B
  $X = NCl_{3} + 3 HCl ; Y = 6 NH_{4}Cl + N_{2}$
• C
  $X = NCl_{3} + N_{2} ; Y = 6 NH_{4}Cl + 3 HCl$
• D
  $X = 6 NH_{4}Cl + 3 HCl ; Y = NCl_{3} + N_{2}$