$(a)$ State Modern Periodic Law.
$(b)$ Elements $A, B, C$ and $D$ have atomic numbers $1, 8, 11$ and $19$ respectively. Choose the odd element and give reason for your answer.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(B) The Modern Periodic Law states that the properties of elements are a periodic function of their atomic numbers.
$(b)$ The odd element is $B$ (atomic number $8$).
Reason: The electronic configuration of $A$ $(Z=1)$ is $1$,$C$ $(Z=11)$ is $2, 8, 1$,and $D$ $(Z=19)$ is $2, 8, 8, 1$. All these elements $(A, C, D)$ have $1$ electron in their valence shell and belong to Group $1$ (alkali metals). However,$B$ $(Z=8)$ has an electronic configuration of $2, 6$,meaning it has $6$ electrons in its valence shell and belongs to Group $16$.

Explore More

Similar Questions

Find the atomic number of the element whose electronic configuration is $2, 8, 5$.

$(a)$ Identify the element that has two completely filled shells and the number of valence electrons in each are as: $(i)$ $1$,$(ii)$ $2$,$(iii)$ $7$,$(iv)$ $8$. $(b)$ Analyse which amongst them is inert.

Which one of the following elements exhibits the maximum number of valence electrons?

Which of the following sets of elements is written in the order of their increasing metallic character?

When Mendeleev started his work,the number of known elements were:

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo