$(a)$ Electric fuse is an important component of all domestic circuits. Why?
$(b)$ An electric oven of rating $2 \, kW, 220 \, V$ is operated in a domestic circuit with a current rating of $5 \, A$. What result would you expect? Explain.

(B) An electric fuse is a safety device used in electrical circuits to prevent damage from excessive current flow. It protects appliances and wiring from fire hazards caused by short-circuiting or overloading.
$(b)$ The current drawn by the electric oven is calculated using the formula $I = P / V$.
Given: $P = 2000 \, W$ and $V = 220 \, V$.
$I = 2000 / 220 = 9.09 \, A$.
Since the current drawn $(9.09 \, A)$ is significantly higher than the circuit's rated capacity of $5 \, A$,the fuse will melt and break the circuit,preventing potential damage or fire.