A uniform rod of mass M and length L is place | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The motion of the centre of mass of a system of particles is governed by the net external force acting on the system.According to Newton's second

Vedclass · Accepted Answer

$F/M$

Vedclass · Answer

(A) The motion of the centre of mass of a system of particles is governed by the net external force acting on the system.According to Newton's second law for the centre of mass:$F_{ext} = M_{total} \cdot a_{cm}$Here,the net external force acting on the rod is $F$.The total mass of the rod is $M$.Therefore,the acceleration of the centre of mass $a_{cm}$ is given by:$a_{cm} = \frac{F_{ext}}{M_{total}} = \frac{F}{M}$Thus,the acceleration of the centre of mass is $F/M$.

$A$ uniform rod of mass $M$ and length $L$ is placed on a smooth horizontal surface. $A$ horizontal force $F$ is applied at one end of the rod perpendicular to its length. The acceleration of the centre of mass of the rod is:

Similar Questions

If $s$ and $p$ are respectively the sum and the product of the slopes of the lines $3x^2 - 2xy - 15y^2 = 0$,then $s:p$ is equal to

If the foci of the ellipse $\frac{x^2}{25}+\frac{y^2}{16}=1$ and the hyperbola $\frac{x^2}{4}-\frac{y^2}{b^2}=1$ coincide,then $b^2$ is equal to

The energy of an electron in the $n^{th}$ orbit of a hydrogen atom is expressed as $E_n = \frac{-13.6}{n^2} \text{ eV}$. The shortest and longest wavelengths of the Lyman series are:

Helium mixed with oxygen is used in the treatment of

From which of the following can a milk-like substance be prepared?

Vedclass Test Series

Exam Paper Generator

Online Exam Module