The products A and B formed in the above reac | vedclass

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Question

(A) In the first reaction,$1$-methylcyclohexanol undergoes acid-catalyzed dehydration using $20\% \ H_3PO_4$ at $358 \ K$. This follows an $E_1$ mecha

Vedclass · Accepted Answer

$A$ = $1-$methylcyclohexene,$B$ = methylenecyclohexane

Vedclass · Answer

(A) In the first reaction,$1$-methylcyclohexanol undergoes acid-catalyzed dehydration using $20\% \ H_3PO_4$ at $358 \ K$. This follows an $E_1$ mechanism,where the more stable,highly substituted alkene (Saytzeff product) is formed as the major product,which is $1-$methylcyclohexene.In the second reaction,$1$-chlorocyclohexane reacts with potassium tert-butoxide $(CH_3)_3COK$,which is a bulky base. This reaction proceeds via an $E_2$ mechanism. Due to the steric hindrance of the bulky base,it abstracts a proton from the less hindered position,leading to the formation of the less substituted alkene (Hofmann product) as the major product,which is methylenecyclohexane.

The products $A$ and $B$ formed in the above reactions are

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