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(B) The reaction of $1	ext{-methyl-1-vinylcyclohexane}$ with $HBr$ proceeds via an electrophilic addition mechanism.$1$. Protonation of the double bo

Vedclass · Accepted Answer

$1-$bromo$-1-$isopropylcyclohexane

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(B) The reaction of $1	ext{-methyl-1-vinylcyclohexane}$ with $HBr$ proceeds via an electrophilic addition mechanism.$1$. Protonation of the double bond occurs to form the most stable carbocation. Initially,a secondary carbocation is formed at the terminal carbon of the vinyl group.$2$. This secondary carbocation undergoes a $1,2	ext{-methyl shift}$ from the cyclohexane ring to the adjacent carbon to form a more stable tertiary carbocation at the ring position.$3$. Finally,the bromide ion $(Br^-)$ attacks this tertiary carbocation to form the major product,which is $1	ext{-bromo-1-isopropylcyclohexane}$.

Predict the major product $A$ for the following reaction:
$1\text{-methyl-1-vinylcyclohexane} + HBr \xrightarrow{CCl_4} A$

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Predict the major product $A$ for the following reaction:$1\text{-methyl-1-vinylcyclohexane} + HBr \xrightarrow{CCl_4} A$