AX is a covalent diatomic molecule where A an | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to Molecular Orbital Theory,the bond order is calculated as $	ext{Bond Order} = \frac{N_b - N_a}{2}$.For a diatomic molecule with $15$

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(B) According to Molecular Orbital Theory,the bond order is calculated as $	ext{Bond Order} = \frac{N_b - N_a}{2}$.For a diatomic molecule with $15$ electrons (like $NO$),the molecular orbital configuration is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^1$.Number of bonding electrons $(N_b)$ = $2+2+2+2+2 = 10$.Number of antibonding electrons $(N_a)$ = $2+2+1 = 5$.$	ext{Bond Order} = \frac{10 - 5}{2} = \frac{5}{2} = 2.5$.Thus,the total number of electrons in $AX$ is $15$.

Pair of species	Identical property
$A$. $B_2 \& O_2$	$P$. Bond order $= 2.5$
$B$. $Be_2 \& H_2^{2-}$	$Q$. Paramagnetic nature
$C$. $N_2^{+} \& N_2^{-}$	$R$. Diamagnetic nature
$D$. $O_2^{+} \& O_2^{-}$	$S$. Doesn't exist

$AX$ is a covalent diatomic molecule where $A$ and $X$ are second row elements of the periodic table. Based on Molecular Orbital Theory,the bond order of $AX$ is $2.5$. The total number of electrons in $AX$ is ........... (Round off to the nearest integer).

Similar Questions

If $x-axis$ is the molecular axis and $p_z$ orbitals participate in bonding,then which one of the following will be the nodal plane present within the $\pi-$ bond of the $O_2$ molecule?

According to molecular orbital theory,the species among the following that does not exist is

Match the following:

Pair of species Identical property

$A$. $B_2 \& O_2$ $P$. Bond order $= 2.5$

$B$. $Be_2 \& H_2^{2-}$ $Q$. Paramagnetic nature

$C$. $N_2^{+} \& N_2^{-}$ $R$. Diamagnetic nature

$D$. $O_2^{+} \& O_2^{-}$ $S$. Doesn't exist

Arrange the following in the increasing order of their bond order: $O_{2}, O_{2}^{+}, O_{2}^{-}, O_{2}^{2-}$

Find the odd-electron molecules from the following:
$(i) C_2, (ii) H_2, (iii) SCl_2, (iv) NO, (v) NO_2$

Vedclass Test Series

Exam Paper Generator

Online Exam Module