$F_2$ is formed by reacting $K_2MnF_6$ with:

  • A
    $SbF_5$
  • B
    $MnF_3$
  • C
    $KSbF_6$
  • D
    $MnF_4$

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Which of the following groups of elements form anions?

$Br_2 + F_2$ (Excess) $\xrightarrow{\Delta} BrF_5$. When $F_2$ is diluted with $N_2$ gas,then the product of $Br$ would be:

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