CuSO_4 reacts with KCN solution and forms: | vedclass

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Question

(A) When $CuSO_4$ reacts with an excess of $KCN$ solution,it initially forms a precipitate of $Cu(CN)_2$,which is unstable and decomposes to form $CuC

Vedclass · Accepted Answer

$K_3[Cu(CN)_4]$

Vedclass · Answer

(A) When $CuSO_4$ reacts with an excess of $KCN$ solution,it initially forms a precipitate of $Cu(CN)_2$,which is unstable and decomposes to form $CuCN$ and cyanogen gas $(CN)_2$. The $CuCN$ then reacts with excess $KCN$ to form the stable complex $K_3[Cu(CN)_4]$. The overall balanced chemical equation is: $2CuSO_4 + 10KCN 	o 2K_3[Cu(CN)_4] + 2K_2SO_4 + (CN)_2$.

$CuSO_4$ reacts with $KCN$ solution and forms:

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