CuSO_4 reacts with KCN solution and forms | vedclass

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Question

(D) When $CuSO_4$ reacts with an excess of $KCN$ solution,it first forms a precipitate of $Cu(CN)_2$,which is unstable and decomposes to form $CuCN$ a

Vedclass · Accepted Answer

$K_3[Cu(CN)_4]$

Vedclass · Answer

(D) When $CuSO_4$ reacts with an excess of $KCN$ solution,it first forms a precipitate of $Cu(CN)_2$,which is unstable and decomposes to form $CuCN$ and $(CN)_2$. $2CuSO_4 + 4KCN 	o 2CuCN + (CN)_2 + 2K_2SO_4$ $CuCN$ then reacts with excess $KCN$ to form the stable complex $K_3[Cu(CN)_4]$. $CuCN + 3KCN 	o K_3[Cu(CN)_4]$ The overall reaction is: $2CuSO_4 + 10KCN 	o 2K_3[Cu(CN)_4] + (CN)_2 + 2K_2SO_4$ Thus,the final product is $K_3[Cu(CN)_4]$.

$CuSO_4$ reacts with $KCN$ solution and forms

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