1-chlorobutane reacts with alcoholic KOH to f | vedclass

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Question

(A) The reaction of $1-$chlorobutane with alcoholic $KOH$ is a dehydrohalogenation reaction (an elimination reaction).In this reaction,a hydrogen atom

Vedclass · Accepted Answer

$1-$butene

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(A) The reaction of $1-$chlorobutane with alcoholic $KOH$ is a dehydrohalogenation reaction (an elimination reaction).In this reaction,a hydrogen atom is removed from the $\beta$-carbon and the chlorine atom is removed from the $\alpha$-carbon,resulting in the formation of an alkene.$CH_3CH_2CH_2CH_2-Cl + KOH(	ext{alc.}) 	o CH_3CH_2CH=CH_2 + KCl + H_2O$.The product formed is $1-$butene.

$1-$chlorobutane reacts with alcoholic $KOH$ to form

Similar Questions

Identify the product '$B$' in the following reaction sequence:
$CH_3CH_2CH(OH)CH_3 \xrightarrow{PBr_3} A \xrightarrow{Mg, \text{dry ether}} B$

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