2, 6-text{Dimethylheptane} on monochlorinatio | vedclass

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Question

(D) The structure of $2, 6-	ext{dimethylheptane}$ is $CH_3-CH(CH_3)-CH_2-CH_2-CH_2-CH(CH_3)-CH_3$. To determine the number of monochlorinated derivat

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(D) The structure of $2, 6-	ext{dimethylheptane}$ is $CH_3-CH(CH_3)-CH_2-CH_2-CH_2-CH(CH_3)-CH_3$. To determine the number of monochlorinated derivatives,we identify the non-equivalent hydrogen atoms in the molecule. $1$. The two terminal $CH_3$ groups at the $2$-position are equivalent. $2$. The $CH$ group at the $2$-position is unique. $3$. The $CH_2$ group at the $3$-position is unique. $4$. The $CH_2$ group at the $4$-position is unique. Due to the symmetry of the molecule,the $CH_2$ at $5$-position is equivalent to the $CH_2$ at $3$-position,the $CH$ at $6$-position is equivalent to the $CH$ at $2$-position,and the $CH_3$ at $7$-position is equivalent to the $CH_3$ at $1$-position. Thus,there are $4$ distinct types of hydrogen atoms available for substitution,leading to $4$ monochlorinated derivatives.

$2, 6-\text{Dimethylheptane}$ on monochlorination produces $...$ derivatives.

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