A xrightarrow{K_2Cr_2O_7 / text{dil. } H_2SO_ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The final product is $tert$-butyl alcohol,which is a tertiary alcohol formed by the reaction of a ketone with a Grignard reagent.Step $1$: The rea

Vedclass · Accepted Answer

$CH_3-CH(OH)-CH_3$

Vedclass · Answer

(B) The final product is $tert$-butyl alcohol,which is a tertiary alcohol formed by the reaction of a ketone with a Grignard reagent.Step $1$: The reaction $B \xrightarrow{CH_3MgI / H_2O} CH_3-C(CH_3)(OH)-CH_3$ indicates that $B$ must be acetone $(CH_3-CO-CH_3)$.Step $2$: The reaction $A \xrightarrow{K_2Cr_2O_7 / 	ext{dil. } H_2SO_4} B$ shows that $A$ is an alcohol that oxidizes to acetone. Secondary alcohols oxidize to ketones.Therefore,$A$ is isopropyl alcohol $(CH_3-CH(OH)-CH_3)$.

$A$ $\xrightarrow{K_2Cr_2O_7 / \text{dil. } H_2SO_4} B$ $\xrightarrow{CH_3MgI / H_2O} CH_3-C(CH_3)(OH)-CH_3$. The reactant $A$ is:

Similar Questions

When primary alcohol is oxidized with chlorine,it produces

$CH \equiv CH$ $\xrightarrow{\text{Red hot Fe tube}} A$ $\xrightarrow{CH_3COCl / AlCl_3} B$ $\xrightarrow{(1) LiAlH_4 / (2) H_3O^\oplus} C$
$C$ will be

The major product of the following reaction is $:-$
$CH_3-CH(CH_3)-CH(OH)-CH_3 \xrightarrow{HBr} \text{Major Product}$

The following reaction is known as:
$C_2H_5OH + SOCl_2 \xrightarrow{\text{Pyridine}} C_2H_5Cl + SO_2 + HCl$

What is denatured alcohol?

Vedclass Test Series

Exam Paper Generator

Online Exam Module