$CH_2 = CH_2 + B_2H_6 \xrightarrow[H_2O_2]{NaOH} \text{Product}$.
The product in the above reaction is:

  • A
    $CH_3CH_2CHO$
  • B
    $CH_3CH_2OH$
  • C
    $CH_3CHO$
  • D
    None of these

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