A normal woman,whose father was colour blind, | vedclass

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(A) $1$. Colour blindness is an $X$-linked recessive trait.$2$. The woman is normal but her father was colour blind,so she must be a carrier $(XX^c)$.

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$25$

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(A) $1$. Colour blindness is an $X$-linked recessive trait.$2$. The woman is normal but her father was colour blind,so she must be a carrier $(XX^c)$.$3$. The man is normal $(XY)$.$4$. The cross is $XX^c 	imes XY$.$5$. The Punnett square results are:- $XX$ (Normal daughter)- $XX^c$ (Carrier daughter)- $XY$ (Normal son)- $X^cY$ (Colour blind son)$6$. Out of four possible outcomes,one $(X^cY)$ is colour blind.$7$. Therefore,the probability of colour blindness in the progeny is $1/4$ or $25\;\%$.

$A$ normal woman,whose father was colour blind,marries a normal man. What is the chance of occurrence of colour blindness in the progeny (in $;\%$)?

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