CH_3 - CH_2 - C equiv CH xrightarrow{HgSO_4, | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction of an alkyne with water in the presence of $HgSO_4$ and $H_2SO_4$ is an electrophilic addition reaction that follows Markovnikov's ru

Vedclass · Accepted Answer

$CH_3 - CH_2 - C(=O) - CH_3$

Vedclass · Answer

(A) The reaction of an alkyne with water in the presence of $HgSO_4$ and $H_2SO_4$ is an electrophilic addition reaction that follows Markovnikov's rule.First,the alkyne $CH_3 - CH_2 - C \equiv CH$ undergoes hydration to form an unstable enol intermediate: $CH_3 - CH_2 - C(OH) = CH_2$.This enol intermediate then undergoes tautomerization to form a more stable keto form.The final product $A$ is butan$-2-$one,which is represented as $CH_3 - CH_2 - C(=O) - CH_3$.

$CH_3 - CH_2 - C \equiv CH \xrightarrow{HgSO_4, H_2SO_4} A$,the compound $A$ is

Similar Questions

$Ph-CH_2-CH=CH-CH_3$ $\xrightarrow[(ii) \text{ Alc. KOH}]{(i) \text{ } Br_2}$ ?

Which of the following gives $H_2$ gas with $Na$?

The shortest $C-C$ bond length is present in:

The treatment of $CH_3MgX$ with $CH_3-C \equiv CH$ produces

$A$ compound $C_5H_8$ gives a white precipitate with ammoniacal $AgNO_3$. It yields $(CH_3)_2CHCOOH$ upon oxidation with hot alkaline $KMnO_4$. The compound is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module