Ge (Z=32) in its ground state electronic conf | vedclass

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(D) The electronic configuration of $Ge$ $(Z=32)$ is $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^2$.We need to identify completely filled orbitals where

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$7$

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(D) The electronic configuration of $Ge$ $(Z=32)$ is $1s^2 2s^2 2p^6 3s^2 3p^6 4s^2 3d^{10} 4p^2$.We need to identify completely filled orbitals where the magnetic quantum number $m_l = 0$.- $1s$ orbital $(m_l=0)$: $1$ orbital (completely filled)- $2s$ orbital $(m_l=0)$: $1$ orbital (completely filled)- $2p$ subshell $(m_l=-1, 0, +1)$: $1$ orbital with $m_l=0$ (completely filled)- $3s$ orbital $(m_l=0)$: $1$ orbital (completely filled)- $3p$ subshell $(m_l=-1, 0, +1)$: $1$ orbital with $m_l=0$ (completely filled)- $4s$ orbital $(m_l=0)$: $1$ orbital (completely filled)- $3d$ subshell $(m_l=-2, -1, 0, +1, +2)$: $1$ orbital with $m_l=0$ (completely filled)- $4p$ subshell: Not completely filled.Total count of completely filled orbitals with $m_l=0$ is $1+1+1+1+1+1+1 = 7$.Thus,$x = 7$.

$Ge$ $(Z=32)$ in its ground state electronic configuration has $x$ completely filled orbitals with $m_{l}=0$. The value of $x$ is ..... .

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