CH_3-CHO + CH_3-MgBr rightarrow text{Product} | vedclass

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Question

(B) Acetaldehyde $(CH_3-CHO)$ reacts with methylmagnesium bromide $(CH_3-MgBr)$ to form an addition product,which upon hydrolysis yields propan-$2$-ol

Vedclass · Accepted Answer

Secondary alcohol

Vedclass · Answer

(B) Acetaldehyde $(CH_3-CHO)$ reacts with methylmagnesium bromide $(CH_3-MgBr)$ to form an addition product,which upon hydrolysis yields propan-$2$-ol $(CH_3-CH(OH)-CH_3)$.Since the $-OH$ group is attached to a carbon atom which is further attached to two other carbon atoms,it is a secondary alcohol.The reaction is: $CH_3-CHO + CH_3-MgBr$ $\rightarrow CH_3-CH(OMgBr)-CH_3$ $\xrightarrow{H_2O} CH_3-CH(OH)-CH_3 + Mg(OH)Br$.

List-$I$ (Reaction)	List-$II$ (Product)
$A$. $\text{Ketone} + NaBH_4$	$I$. $1^\circ$-alcohol
$B$. $\text{Ester} + LiAlH_4$	$II$. $3^\circ$-alcohol
$C$. $RMgX + \text{Ketone}$	$III$. $2^\circ$-alcohol
	$IV$. $\text{Alkane}$

$CH_3-CHO + CH_3-MgBr$ $\rightarrow \text{Product}$ $\xrightarrow{H_2O} A$. What is $A$?

Similar Questions

Which of the following aldehydes is less reactive towards nucleophilic addition reaction?

Match the following reactions in List-$I$ with their products in List-$II$.
List-$I$ (Reaction) List-$II$ (Product)
$A$. $\text{Ketone} + NaBH_4$ $I$. $1^\circ$-alcohol
$B$. $\text{Ester} + LiAlH_4$ $II$. $3^\circ$-alcohol
$C$. $RMgX + \text{Ketone}$ $III$. $2^\circ$-alcohol
$IV$. $\text{Alkane}$

Aldehydes and ketones can be reduced to hydrocarbons by using:

Identify the final product in the following reaction sequence: $R-CHO$ $\xrightarrow{HS-(CH_2)_3-SH}$ $\xrightarrow{n-BuLi}$ $\xrightarrow{D_2O}$ $\xrightarrow{HgCl_2/CdCO_3, H_2O} \text{Product}$

What is the product $E$ in the following reaction?

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