$CH_3COOC_2H_5$ with excess of $C_2H_5MgBr$ and hydrolysis gives:

  • A
    $CH_3-CO-C_2H_5$
  • B
    $CH_3-C(OH)(C_2H_5)_2$
  • C
    $CH_3-CO-CH_3$
  • D
    $CH_3-C(=O)(C_2H_5)-CH_3$

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