C_6H_5CHO + HCN to C_6H_5-CH(OH)-CN. The prod | vedclass

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Question

(A) The reaction of benzaldehyde $(C_6H_5CHO)$ with hydrogen cyanide $(HCN)$ produces benzaldehyde cyanohydrin $(C_6H_5-CH(OH)-CN)$.In this product,th

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$A$ racemate

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(A) The reaction of benzaldehyde $(C_6H_5CHO)$ with hydrogen cyanide $(HCN)$ produces benzaldehyde cyanohydrin $(C_6H_5-CH(OH)-CN)$.In this product,the carbon atom attached to the phenyl group,hydroxyl group,cyano group,and hydrogen atom is a chiral center.Since the starting material $(C_6H_5CHO)$ is planar,the nucleophilic attack by $CN^-$ can occur from either side of the carbonyl group with equal probability.This leads to the formation of an equal mixture of both enantiomers,resulting in a racemic mixture (racemate).

$C_6H_5CHO + HCN \to C_6H_5-CH(OH)-CN$. The product would be

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