X is heated with soda lime and gives ethane. | vedclass

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(C) The reaction of a carboxylic acid with soda lime $(NaOH + CaO)$ is known as decarboxylation.In this process,the carboxylic acid loses a molecule o

Vedclass · Accepted Answer

Propanoic acid

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(C) The reaction of a carboxylic acid with soda lime $(NaOH + CaO)$ is known as decarboxylation.In this process,the carboxylic acid loses a molecule of $CO_2$ to form an alkane with one carbon atom less than the parent acid.To obtain ethane ($C_2H_6$,which has $2$ carbon atoms),the starting carboxylic acid must have $3$ carbon atoms.Therefore,$X$ is propanoic acid $(C_2H_5COOH)$.Reaction: $C_2H_5COOH + NaOH \xrightarrow{CaO} C_2H_6 + Na_2CO_3$.

$X$ is heated with soda lime and gives ethane. $X$ is

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