p-Nitrobromobenzene can be converted to p-nit | vedclass

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Question

(C) The reaction of $p-$nitrobromobenzene with $NaNH_2$ proceeds via an elimination-addition mechanism.In the first step,the strong base $NH_2^-$ abst

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Benzyne

Vedclass · Answer

(C) The reaction of $p-$nitrobromobenzene with $NaNH_2$ proceeds via an elimination-addition mechanism.In the first step,the strong base $NH_2^-$ abstracts a proton from the ortho position to the bromine atom,followed by the elimination of the bromide ion $(Br^-)$ to form a highly reactive intermediate known as a benzyne (specifically,a substituted benzyne or aryne intermediate).Subsequently,the nucleophile $NH_3$ attacks the benzyne intermediate to form $p-$nitroaniline.Therefore,the intermediate formed is a benzyne.

$p-$Nitrobromobenzene can be converted to $p-$nitroaniline by using $NaNH_2$. The reaction proceeds through the intermediate named

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