R-NH-CHO xrightarrow[text{pyridine}]{POCl_3} | vedclass

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(B) The reaction of $N$-alkyl formamides with $POCl_3$ in the presence of pyridine is a dehydration reaction.This process leads to the formation of is

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$R-N \equiv C$

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(B) The reaction of $N$-alkyl formamides with $POCl_3$ in the presence of pyridine is a dehydration reaction.This process leads to the formation of isocyanides (also known as carbylamines).The reaction is represented as: $R-NH-CHO \xrightarrow[	ext{pyridine}]{POCl_3} R-NC + H_2O$.Therefore,the correct product is $R-NC$ (which is $R-N \equiv C$).

$R-NH-CHO \xrightarrow[\text{pyridine}]{POCl_3} \text{ product}$
In the given reaction,what will be the product?

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$R-NH-CHO \xrightarrow[\text{pyridine}]{POCl_3} \text{ product}$In the given reaction,what will be the product?