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(D) Fructose $1,6$-bisphosphate is a $6$-carbon compound that enters glycolysis. $1$. Fructose $1,6$-bisphosphate splits into two molecules of Glycera

Vedclass · Accepted Answer

$12$

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(D) Fructose $1,6$-bisphosphate is a $6$-carbon compound that enters glycolysis. $1$. Fructose $1,6$-bisphosphate splits into two molecules of Glyceraldehyde $3$-phosphate $(G3P)$. $2$. Each $G3P$ molecule undergoes glycolysis to produce $2$ $NADH$,$2$ $ATP$,and $1$ Pyruvate. Thus,two $G3P$ molecules produce $4$ $NADH$ and $4$ $ATP$. $3$. The two Pyruvate molecules enter the Link Reaction to produce $2$ $NADH$. $4$. The two Acetyl-$CoA$ molecules enter the Krebs cycle to produce $6$ $NADH$,$2$ $FADH_2$,and $2$ $ATP$ (or $GTP$). $5$. Total yield: $12$ $NADH$ ($12 	imes 2.5 = 30$ $ATP$),$2$ $FADH_2$ ($2 	imes 1.5 = 3$ $ATP$),and $4$ $ATP$ (direct). $6$. Total $ATP = 30 + 3 + 4 = 37$ $ATP$. However,in many standard textbook calculations (using $3$ $ATP$ per $NADH$ and $2$ $ATP$ per $FADH_2$),the total is $38$ $ATP$. $7$. Since Fructose $1,6$-bisphosphate is already phosphorylated,it bypasses the initial investment phase of glycolysis (which consumes $2$ $ATP$). Therefore,the net yield is $38$ $ATP$.

How many $ATP$ molecules are produced during the complete oxidation of one molecule of fructose $1,6$-bisphosphate?

Similar Questions

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