In Mendel's dihybrid cross,what percentage of | vedclass

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(C) In a Mendelian dihybrid cross involving two traits (e.g.,seed shape and seed color),the $F_2$ generation is produced by selfing the $F_1$ dihybrid

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$25$

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(C) In a Mendelian dihybrid cross involving two traits (e.g.,seed shape and seed color),the $F_2$ generation is produced by selfing the $F_1$ dihybrid $(RrYy 	imes RrYy)$.According to the Punnett square for a dihybrid cross,the total number of combinations is $16$.The genotype $RrYy$ appears $4$ times in the $16$ possible combinations.Therefore,the percentage is calculated as: $(4 / 16) 	imes 100 = 25 \,\%$.

In Mendel's dihybrid cross,what percentage of the $F_2$ generation possesses the $RrYy$ genotype (in $,\%$)?

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