Bacteria containing ^{15}N-DNA are grown in a | vedclass

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(B) The replication of $DNA$ is semi-conservative. Starting with $1$ molecule of $^{15}N-DNA$ (heavy),after each generation of $20$ minutes,the number

Vedclass · Accepted Answer

$0$ heavy : $7$ light : $1$ hybrid

Vedclass · Answer

(B) The replication of $DNA$ is semi-conservative. Starting with $1$ molecule of $^{15}N-DNA$ (heavy),after each generation of $20$ minutes,the number of $DNA$ molecules doubles. $80$ minutes corresponds to $80/20 = 4$ generations. Total $DNA$ molecules after $4$ generations = $2^4 = 16$. In semi-conservative replication,only $2$ molecules will be hybrid $(^{15}N-^{14}N)$ and the remaining $(16 - 2) = 14$ molecules will be light $(^{14}N-^{14}N)$. Ratio of heavy : light : hybrid = $0 : 14 : 2$. Simplifying the ratio by dividing by $2$,we get $0 : 7 : 1$. Thus,there are $0$ heavy,$7$ light,and $1$ hybrid $DNA$ molecules.

Bacteria containing $^{15}N-DNA$ are grown in a medium containing $^{14}NH_4Cl$ for $80$ minutes. What will be the proportion of $DNA$?

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