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Question

(C) According to the species-area relationship proposed by Alexander von Humboldt,the relationship between species richness and area is a rectangular

Vedclass · Accepted Answer

$1.15$

Vedclass · Answer

(C) According to the species-area relationship proposed by Alexander von Humboldt,the relationship between species richness and area is a rectangular hyperbola. On a logarithmic scale,this relationship becomes a straight line described by the equation $\log S = \log C + Z \log A$. Here,$S$ is species richness,$A$ is area,$Z$ is the slope of the line (regression coefficient),and $C$ is the $Y$-intercept. For smaller areas,the value of $Z$ generally ranges from $0.1$ to $0.2$. However,for very large areas like the entire continent or for specific groups like frugivorous birds and mammals in tropical forests,the slope of the $Z$ line is much steeper,typically around $1.15$.

Column-$I$ (Location)	Column-$II$ (Number of Bird Species)
$P$. Colombia	$I$. $56$
$Q$. New York	$II$. $105$
$R$. Greenland	$III$. $1200$
$S$. India	$IV$. $1400$
$T$. Amazonian rain forest	$V$. $1300$

In the tropical forests of different continents,the slope of the $Z$ line for frugivorous birds and mammals is found to be $...........$.

Similar Questions

What is the significance of the slope of regression in a species-area relationship?

Match the following locations with the number of bird species found there:

Column-$I$ (Location) Column-$II$ (Number of Bird Species)

$P$. Colombia $I$. $56$

$Q$. New York $II$. $105$

$R$. Greenland $III$. $1200$

$S$. India $IV$. $1400$

$T$. Amazonian rain forest $V$. $1300$

Which is not a reason for maximum diversity in the tropics?

The relationship between species richness $(S)$ and area $(A)$ represented in the following graph is described by the equation:

What is the exact latitudinal range for tropical regions,which harbour more species than temperate or polar areas?

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