Given S = species richness,A = area,Z = slope | vedclass

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(A) The relationship between species richness and area is given by the equation $S = CA^Z$. Taking the logarithm on both sides,we get $\log S = \log C

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(A) The relationship between species richness and area is given by the equation $S = CA^Z$. Taking the logarithm on both sides,we get $\log S = \log C + Z \log A$. This equation is in the form of a linear equation $y = mx + c$,where $y = \log S$,$x = \log A$,$m = Z$ (slope),and $c = \log C$ ($Y$-intercept). Since $Z$ (the slope of the regression) is a positive value,the graph of $\log S$ versus $\log A$ represents a straight line with a positive slope.

Given $S =$ species richness,$A =$ area,$Z =$ slope of the line,and $C =$ $Y$-intercept. If area is on the $X$-axis and species richness is on the $Y$-axis,what will the graph of $\log S = \log C + Z \log A$ look like?

Similar Questions

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