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(D) The energy released $Q$ in a nuclear reaction is given by the mass defect multiplied by the energy equivalent of $1 \, u$ $(931.5 \, MeV/c^2)$.Mas

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$4.25$

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(D) The energy released $Q$ in a nuclear reaction is given by the mass defect multiplied by the energy equivalent of $1 \, u$ $(931.5 \, MeV/c^2)$.Mass defect $\Delta m = (m_A - m_B - m_D)$.$\Delta m = (238.05079 - 234.04363 - 4.00260) \, u$.$\Delta m = 238.05079 - 238.04623 = 0.00456 \, u$.Energy released $Q = \Delta m 	imes 931.5 \, MeV/u$.$Q = 0.00456 	imes 931.5 \, MeV \approx 4.24764 \, MeV$.Rounding to the nearest value,$Q \approx 4.25 \, MeV$.

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