2-Methylpropyl bromide reacts with C_2H_5O^- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Reaction with $C_2H_5O^-$: $C_2H_5O^-$ is a strong nucleophile. $2-$Methylpropyl bromide is a primary alkyl halide. Therefore,it undergoes an $S_N

Vedclass · Accepted Answer

$S_N2$,$A =$ isobutyl ethyl ether; $S_N1$,$B =$ tert-butyl ethyl ether

Vedclass · Answer

(A) Reaction with $C_2H_5O^-$: $C_2H_5O^-$ is a strong nucleophile. $2-$Methylpropyl bromide is a primary alkyl halide. Therefore,it undergoes an $S_N2$ reaction to form isobutyl ethyl ether $(A)$.Reaction with $C_2H_5OH$: $C_2H_5OH$ is a weak nucleophile. The reaction proceeds via an $S_N1$ mechanism. The primary carbocation formed initially undergoes a $1,2-H$ shift to form a more stable tertiary carbocation,which then reacts with the nucleophile to form tert-butyl ethyl ether $(B)$.

$2-$Methylpropyl bromide reacts with $C_2H_5O^-$ to give $A$,whereas on reaction with $C_2H_5OH$ it gives $B$. The mechanism followed in these reactions and the products $A$ and $B$ respectively are:

Similar Questions

In a nucleophilic substitution reaction,the order of halogens as incoming (attacking) nucleophiles is: $I^{-} > Br^{-} > Cl^{-}$. The order of halogens as departing (leaving) nucleophiles should be:

Identify the major product $Y$ in the given reaction sequence.

Which among the following statements is $TRUE$ about gammexane?

Reaction $(A)$:
$Ph-CH=CH-CH_3 \xrightarrow[H_2O_2 / OH^-]{B_2H_6 / THF}$ products.
Reaction $(B)$:
$CH_3-CH=CH-Ph \xrightarrow[NaBH_4]{Hg(OAc)_2 / H_2O}$ products.
Correct statement is:

$2CHCl_3 + O_2 \xrightarrow{X} 2COCl_2 + 2HCl$. In the above reaction,$X$ stands for:

Vedclass Test Series

Exam Paper Generator

Online Exam Module