A ( g ) rightarrow 2 B ( g ) + C ( g ) is a f | vedclass

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(D) For the reaction $A ( g ) \rightarrow 2 B ( g ) + C ( g )$,let the initial pressure of $A$ be $P_0 = 800 \ mm \ Hg$.At $t = 10 \ min$,the total pr

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(D) For the reaction $A ( g ) ightarrow 2 B ( g ) + C ( g )$,let the initial pressure of $A$ be $P_0 = 800 \ mm \ Hg$.At $t = 10 \ min$,the total pressure $P_t = P_0 - x + 2x + x = P_0 + 2x = 1600 \ mm \ Hg$.Substituting $P_0 = 800$,we get $800 + 2x = 1600$,so $2x = 800$,which means $x = 400 \ mm \ Hg$.The pressure of $A$ remaining at $t = 10 \ min$ is $P_0 - x = 800 - 400 = 400 \ mm \ Hg$.Since the initial pressure was $800 \ mm \ Hg$ and it became $400 \ mm \ Hg$ in $10 \ min$,the half-life $t_{1/2} = 10 \ min$.After $30 \ min$ $(3 	imes t_{1/2})$,the pressure of $A$ remaining is $P_A = P_0 	imes (1/2)^3 = 800 	imes (1/8) = 100 \ mm \ Hg$.The amount of $A$ reacted is $800 - 100 = 700 \ mm \ Hg$.According to stoichiometry,$A ightarrow 2B + C$,the pressure of $B$ produced is $2 	imes 700 = 1400 \ mm \ Hg$ and $C$ produced is $700 \ mm \ Hg$.The total pressure at $t = 30 \ min$ is $P_A + P_B + P_C = 100 + 1400 + 700 = 2200 \ mm \ Hg$.

$S.NO$	$Time/s$	Total pressure $(atm)$
$1.$	$0$	$0.6$
$2.$	$100$	$X$

$A ( g ) \rightarrow 2 B ( g ) + C ( g )$ is a first order reaction. The initial pressure of the system was found to be $800 \ mm \ Hg$ which increased to $1600 \ mm \ Hg$ after $10 \ min$. The total pressure of the system after $30 \ min$ will be . . . . . . $mm \ Hg$. (Nearest integer)

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