20 mL of 0.5 M NaCl is required to coagula | vedclass

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(A) The coagulating value is defined as the minimum concentration of an electrolyte in millimoles per liter $(mmol/L)$ required to cause coagulation o

Vedclass · Accepted Answer

$50$

Vedclass · Answer

(A) The coagulating value is defined as the minimum concentration of an electrolyte in millimoles per liter $(mmol/L)$ required to cause coagulation of a sol in $2$ hours.Given:Volume of $NaCl$ solution = $20 \ mL$Molarity of $NaCl$ solution = $0.5 \ M$Volume of $As_2S_3$ sol = $200 \ mL$Number of millimoles of $NaCl$ = $Molarity 	imes Volume \ (in \ mL) = 0.5 	imes 20 = 10 \ mmol$.These $10 \ mmol$ of $NaCl$ are required for $200 \ mL$ of sol.For $1000 \ mL$ $(1 \ L)$ of sol,the required millimoles = $(10 / 200) 	imes 1000 = 50 \ mmol/L$.Therefore,the coagulating value of $NaCl$ is $50$.

$20 \ mL$ of $0.5 \ M \ NaCl$ is required to coagulate $200 \ mL$ of $As_2S_3$ sol in $2$ hours. The coagulating value of $NaCl$ is $...........$.

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