3-Methylhex-2-ene on reaction with HBr in the | vedclass

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(A) The reaction of $3-$methylhex$-2-$ene with $HBr$ in the presence of peroxide follows the anti-Markovnikov addition mechanism.The product $(A)$ for

Vedclass · Accepted Answer

$4$

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(A) The reaction of $3-$methylhex$-2-$ene with $HBr$ in the presence of peroxide follows the anti-Markovnikov addition mechanism.The product $(A)$ formed is $2-$bromo$-3-$methylhexane.The structure of $2-$bromo$-3-$methylhexane is $CH_3-CH(Br)-CH(CH_3)-CH_2-CH_2-CH_3$.This molecule contains $2$ chiral centers at $C-2$ and $C-3$.Since the two chiral centers are not equivalent (the groups attached to them are different),the number of stereoisomers is given by $2^n$,where $n$ is the number of chiral centers.Number of stereoisomers $= 2^2 = 4$.

$3-$Methylhex$-2-$ene on reaction with $HBr$ in the presence of peroxide forms an addition product $(A)$. The number of possible stereoisomers for '$A$' is $....$.

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